8/3(x^2)=216

Solution for 8/3(x^2)=216 equation:

8/3(x^2)=216

We move all terms to the left:

8/3(x^2)-(216)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-216*3x^2+8=0

Wy multiply elements

-648x^2+8=0

a = -648; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-648)·8
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*-648}=\frac{-144}{-1296}
=1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*-648}=\frac{144}{-1296}
=-1/9
$